Use implicit differentiation to get:
y'(x)=-x/(π cos 2πy)
Plug in (3,8) into this equation to get the slope of the tangent line.
The equation of the tangent will be y'(3) = (y-8)/(x-3)
Rahman W.
asked 11/13/19find y',y'(3) and the equation of the tangent line to the curve, x^2+(sin(2*pi*y)) = 9, at the point (3,8)
1) the derivative of x is given by y'=.....
2)the slope of the tangent line to the curve at (3,8) is given by y'(3)=....
3)the equation of the tangent line to the curve (3,8) is given by y=.....
Use implicit differentiation to get:
y'(x)=-x/(π cos 2πy)
Plug in (3,8) into this equation to get the slope of the tangent line.
The equation of the tangent will be y'(3) = (y-8)/(x-3)
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