Inactive Tutor answered 11/12/19
You are given two points, (0,6) and (3,-3), so use the two-point formula for the equation of a line:
y - y1 = ( (y2 - y1) / (x2 - x1) ) (x - x1)
y - 6 = ( -9 / 3 ) (x - 0)
y - 6 = -3x
y = -3x + 6 This is: y = mx+b
Haley F.
asked 11/12/19Inactive Tutor answered 11/12/19
You are given two points, (0,6) and (3,-3), so use the two-point formula for the equation of a line:
y - y1 = ( (y2 - y1) / (x2 - x1) ) (x - x1)
y - 6 = ( -9 / 3 ) (x - 0)
y - 6 = -3x
y = -3x + 6 This is: y = mx+b
Inactive Tutor answered 11/12/19
Slope-Intercept form: y = mx + b, where m is the slope and b is the y-intercept (where x = 0)
You are given the x and y dimensions for 2 points. Plug these into the general form to create 2 equations where m and b are the unknowns. Solve this pair using the one of the standard methods.
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