find it please:)

Question

Kevin and Randy Muise have a jar containing

58 coins, all of which are either quarters or nickels. The total value of the coins in the jar is

​$5.50.

How many of each type of coin do they​ have?

Answer 1

You have 2 unknowns, and you therefor need 2 equations. Let Q = the number of quarters, and N equal the number of nickels..

The first equation is simply N + Q = 58

To get the second equation, write the value of the nickels and quarters, and add them to get the given total value. The value of the nickels is 0.05*N, and of the quarters: 0.25*Q

Once you have the 2 equations, then solve using either elimination or substitution

Answer 2

Hi Sad. This one only looks scary.

We know:

1. 58 coins, only nickels (N) and quarters (Q)
2. $5.50 total value

From this information we can conclude:

1. Q + N = 58
2. 5.50 = .25*Q + .05*N

Start with:

1. Q + N = 58
2. Q = 58 - N

Substitute 58 - N for Q in the second equation and solve for N:

1. 5.50 = .25*(58-N) + .05*N
2. 5.50 = 14.50 - .25N + .05N
3. 5.50 = 14.50 -.2N
4. -9 = .2N
5. N = 45

Now take 45 back to the first equation to find the value of Q:

1. Q + N = 58
2. Q + 45 = 58
3. Q = 13

Then check your work:

1. 5.50 = .25*Q + .05*N
2. 5.50 = .25*13 + .05*45
3. 5.50 = 3.25 + 2.25
4. 5.50 = 5.50✔