Write an equation for a line perpendicular to 4 y + 20 x = − 20 4 y + 20 x = - 20 and passing through the point (5,-1)

Answer 1

Perpendicular to 4y+20x = -20 and passes through (5,-1)

1st step: Solve for y in terms of x

4y+20x = -20

-20x -20x

4y= -20-20x

÷4 ÷4

y=-5x-5

2nd Step: Find slope

m=-5

3rd Step: Find perpendicular slope which is the negative reciprocal of the slope of the original line

Perpendicular slope = 1/5

4th Step: Use pass through coordinate (5,-1) and perpendicular slope to find the equation of the line by using the point slope formula y -y₁ = m(x-x₁) and solve for y in terms of x.

y-(-1)=1/5(x-5)

y+1=(1/5)x-1

-1 -1

y=(1/5)x - 2

Done