The equation of the line that goes through the point (4,4) and is parallel to the line 2x+5y=4 can be written in the form y=mx+b where m is: and where b is:

Question

I need help with this problem please!

Answer 1

Let's rearrange the equation 2x+5y=4 to look more like y=mx+b.

2x+5y=4

5y=4-2x

y=(4-2x)/5

y=(4/5)-(2/5)x

So we see that the slope is -2/5.

Using the point (4,4) we can plug those numbers into the equation above, but not including the 4/5, because that b value is specific for the original equation, and we will solve for b.

So,

4=b-(2/5)(4)

4=b-1.6

b=5.6

The equation will be : y=(=2/5)x+5.6