Algebra High School Help

Question

A small plane flies 760,320 yards in 2 hours. Use the formula d = rt, where d represents distance, r represents rate, and t represents time, to answer the following questions. Show your work.

Part A: Rearrange the distance formula, d = rt, to solve for rate. (2 points)

Part B: Find the plane's rate in yards per hour. (3 points)

Part C: Find the plane's rate in miles per hour. (3 points)

Part D: Which unit, yards, or miles, makes more sense to use in this scenario, and why? (2 points)

Answer 1

A) Divide both sides of equation by t to isolate r. Then, r = d/t

B) Plugging in the given numbers, solve r = 760,320 yards / 2 hours = 380,160 yd/hr

C) Looking up the conversion from yards to miles, 1 yard = (1/1760) miles. Then multiply by our answer in (B) by that ratio => (380,160 yd/hr)*(1 mile/1760 yd) = 216 mi/hr

D) Use miles in this scenario because of the number of significant digits (yards would require a number in the hundred-thousands).

Answer 2

Part B: Find the plane's rate in yards per hour.

So rate = yards per hour. That is rate = distance per hour (since yards is a distance).

So r=d/t. Now you have the answer for part a

r=760,320 yards in 2 hours. So r= 760,320 yards / 2 hours

Part A: Rearrange the distance formula, d = rt, to solve for rate.

We already found the answer from part b. You can just divide both sides of d=rt by t and get r = d/t.

There are 5280 ft in 1 mile and 3 ft in 1 yard. Try the rest.