The larger of two number is six less than twice the small number. If the sum of the numbers is 42, find the numbers

Answer 1

The larger of two number is: There are two numbers. Let's call them x and y and x > y. Larger one is x. x =

six less than: x = -6

twice the small number.: x = -6 + 2*y

If the sum of the numbers is 42, find the numbers: x+y = 42

x = 2y - 6

x = -y + 42 (Subtract second equation from the first one to eliminate x)

0 = 3y - 48 (Add 48 to both sides)

48 = 3y (Divide both sides by 3)

y = 16

x = 2y - 6 = 2*16 - 6 = 26

Another way of solving these equations is:

x = 2y - 6

x + y = 42 (Substitute 2y-6 from first equation to x in the second one)

2y - 6 + y = 42 (Add 6 to both sides)

3y = 48 (divide by 3)

y = 16

x = 2y - 6 = 2*16 - 6 = 26