How do i solve this?

Question

The sum of 5 times the width of a rectangle and twice its length is 26 units. The difference of 15 times the width and three times the length is 6 units. Write and solve a system of equations to find the length and width of the rectangle.

Answer 1

Let x = width and y = length

5x + 2y = 26

15x - 3y = 6

Multiply the first equation by -3:

-15x - 6y = -78

15x - 3y = 6

Add the equations: -9y = -72

So, y = 8 and x = 2

The length is 8 and the width is 2.

Answer 2

5w+2L=26

15w-3L=6

=20w-L=32

if w=2; L=8

3 28

4 48.....................