A certain number was increased 5 times, then decreased by 3, then halved. The result was 0.3 less than the original number. What was the original number?

Answer 1

We translate this into algebra.

(5n - 3)/2=n-0.3

Then we solve for n.

Multiply the whole thing by 2.

5n-3=2n-0.6

Add 0.6

5n-2.4=2n

Add 2.4

5n=2n+2.4

Subtract 2n

3n=2.4

Divide by 3

n=0.8