Jennifer Y. answered 10/27/19
Math Teacher in High School
Let the width be W and the length would be W+8
Since 4-feet walkway surrounds the pool, the width and the length of the area including the walkway would be W+8 and W+16 (increased by 4+4=8).
(W+8)(W+16)=1280
W2+24W-1152=0
(W+48)(W-24)=0
W=24 and L=W+*=24+8=32
The dimension of pool is 24 by 32 ft.