The line with equation y = (5/2)x - 2 has slope 5/2.
Any line that is perpendicular to that line has slope -1 / (5/2) = -2/5.
Equation of line with slope -2/5 and containing the point (-4,1) is: y - 1 = (-2/5)(x - (-4))
y = (-2/5)x - 3/5
Heather J.
asked 10/27/19Through (-4,1), perpendicular to y=5/2x-2
Please show all steps so I can help my son - I haven't tried geometry since highschool!
The line with equation y = (5/2)x - 2 has slope 5/2.
Any line that is perpendicular to that line has slope -1 / (5/2) = -2/5.
Equation of line with slope -2/5 and containing the point (-4,1) is: y - 1 = (-2/5)(x - (-4))
y = (-2/5)x - 3/5
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