The sum of three numbers is 8. The first number is six times the second, and the sum of the first and the third is 6. Find the numbers.

Answer 1

Let n, m, and p be the first, second, and third numbers, respectively.

n = 6m

m = ?

n + p = 6 ⇒ p = 6 - n = 6 - 6m

n + m + p = 8 ⇒

6m + m + (6 - 6m) = 8 ⇒

m = 2

n = 6m = 6(2) = 12

p = 6 - 6m = 6 - 6(2) = -6

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