Philip P. answered 10/21/19
Affordable, Experienced, and Patient Algebra Tutor
Whew, this is a busy one. Let's work through it. Let x = the number of guitars and y = the number of basses.
- they can buy no more than 50 instruments total: x + y ≤ 50
- The store’s cost to buy a guitar is $200 and $400 for the basses so the Cost = 200x + 400y. They have $12000 to spend on buying their initial inventory, so 200x + 400y ≤ 12,000
- because guitars are more popular than basses, the numbers of guitars must be at least twice the number of basses: x ≥ 2y
- Their supplier requires a minimum initial purchase of at least 17 guitars and at least 5 basses: x ≥ 17 and y ≥ 5
- each bass will sell for $900 and each guitar sell for $750, so Revenue = 750x + 900y. The Profit = Revenue - Cost = 750x + 900y - (200x + 400y) = 550x + 500y. This is the equation to be maximized by applying linear programming given the above constraints.
Alex P.
Thank you so much! This is really helpful :)10/21/19