What you need is the formula for the derivative of f-1 in terms of f and f'.
Note: this is a completely edited answer...my original answer was not correct.
This method of finding the derivative of the inverse function is probably not in standard form;
it does work, however.
y = x+ x3
Interchange the roles of x and y:
x = y + y3
Differentiate implicitly
1 = dy/dx + 3y2 dy/dx...where dy/dx is the derivative of the INVERSE function
and y = f-1(x)
dy/dx = 1/(1 + 3y2)
I am not sure what is wanted, but if y=2, the slope of the tangent to the inverse function is 1/12