The length of a rectangle is 2 in longer than its width. If the perimeter of the rectangle is 52 in , find its length and width.

Answer 1

Here's what we know:

P = 2L + 2w (the perimeter is its 2 lengths and widths added together)

P = 52 (the perimeter of this rectangle is 52 inches)

L = w + 2 (the length is 2 inches more than the width)

Let's plug the variable values in:

52 = 2(w + 2) + 2w

Distribute:

52 = 2w + 4 + 2w

Combine like terms:

52 = 4w + 4

Subtract 4:

48 = 4w

Divide by 4:

12 = w

Find length:

L = 12 + 2

L = 14

check:

52 = 2 * 14 + 2 * 12

52 = 28 + 24

52 = 52

remember your units of measurement.