Let x be such a number.
Then, x > 11+8 or x < 8-11
x - 8 > 11 or x - 8 < -11
So, l x - 8 l > 11
Antonio V.
asked 10/15/19Let x be such a number.
Then, x > 11+8 or x < 8-11
x - 8 > 11 or x - 8 < -11
So, l x - 8 l > 11
Rebecca R. answered 10/15/19
Experienced Elementary Math, Prealgebra, Algebra 1, and Geometry Tutor
Hello, Antonio.
Okay, so that distance from 8 has to be more than 11 units.
| x - 8 | > 11
So, to solve for x:
If x - 8 is positive, then:
x - 8 > 11
x > 19
If x - 8 is negative, then:
| x - 8| = -(x - 8) = 8 - x
So,
8 - x > 11
x < -3
So, the answers are:
x < -3 or x > 19
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