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Question

the perimeter of a rectangle is 76 inches. the width of the rectangle is 10 inches less than the length of the rectangle. find the dimensions of the rectangle.

Answer 1

P=76 in. P = 2L + 2W, where L and W represent Length and Width, respectively.

It is given that W = L-10.

Thus 2W = 2(L-10) = 2L-20.

76 = 2L + 2L - 20 = 4L - 20

Add 20 to both sides to find

96 = 4L

Divide both sides by 4 to find L = 24

W = L-10 = 24-10 = 14.

Check: 2*24 + 2*14 = 48+28 = 76.