Max A. answered 10/14/19
Professional Engineer with a Strong Tutoring/Academic Background
This problem is a system of three equations with three unknown variables. We have to first come up with the correct equations, then we will solve them.
Let x = # of touchdowns scored (worth 6 pts each)
Let y = # of points after touchdown scored (worth 1 pt each)
Let z = # of field goals scored (worth 3 pts each)
The first sentence of the problems states the team scored 50 points in total. We can write an equation for this as follows:
6x + y + 3z = 50 (call this equation #1)
The next sentence states they scored 14 times. We can write an equation for this as follows:
x + y + z = 14 (equation #2)
Finally, we know the team had three more touchdowns than field goals. This means if we had 1 field goal, there would be 4 touchdowns. 2 field goals would be 5 touchdowns. A general way to write this equation in terms of our variables is as follows:
x = z + 3 (equation #3)
There are many ways to solve these equations. To me, the simplest way is as follows. We will substitute the term for x in equation #3 directly into equations #1 and #2.
6*(z + 3) + y + 3z = 50
6z + 18 + y + 3z = 50
9z + y + 18 = 50
9z + y = 32
Now we will do the same for equation #2.
(z + 3) + y + z = 14
2z + y + 3 = 14
2z + y = 11
We can multiply our now simplified equation #2 by a factor of -1, then we can add it to equation #1.
-2z - y = -11
9z + y = 32 (add these two lines together, to get the resulting line below)
7z = 21
z = 3
Now, we can substitute our answer for z back into equation #3.
x = z + 3
x = 3 + 3
x = 6
Finally, we can substitute our answers for x and z back into the original equation #2.
x + y + z = 14
6 + y + 3 = 14
y = 5
To summarize, the team scored 6 touchdowns, 5 points after touchdown, and 3 field goals. You can verify this answer is correct by substituting into our original equations. All three will come out true.
Dylan L.
Thank you so much! You are a lifesaver! I couldn't figure out how to do this, but now I completely understand.10/14/19