Algebra problem ,, need help

Question

The question is "Two thirds of a number reduced by 11 is equal to 4 more than the number, find the number."

Answer 1

Let's call this number x. Two thirds of a number ...

(2/3)x

reduced by 11 ...

(2/3)x - 11

is equal to

(2/3)x - 11 =

4 more than the number (recall that the number is x)

(2/3)x - 11 = 4 + x

Now we can solve this equation. We need to collect all x terms on one side:

(2/3)x - 11 = 4 + x (add -x to both sides)

(2/3)x -x - 11 = 4

(2/3)x - (3/3)x -11 = 4

(-1/3) x - 11 = 4 (add 11 to both sides)

(-1/3) x = 15 (multiply both sides with -3)

x = -45

Answer 2

(2/3)x - 11 = x + 4

2x - 33 = 3x + 12

x = -45