Slope-intercept form is given as follows:
y = mx + b
Where m is the slope, and b is the y-intercept.
Fun tidbits:
The first variable we're looking for is referred to as 'm' because it is the vertical "move" value.
The second variable is referred to as 'b' because it's where the line "begins".
Right off the bat, we're given the slope of 0. This means we have a flat line! It's not moving.
So far we have:
m = 0
Which we can plug in to our slope-intercept form equation:
y = 0 * x + b
Now we have to figure out what the y-intercept is. The y-intercept is the value of y where the line crosses the y axis, which happens when x is 0. In this case, the value of y will always be whatever b is. So we can use the y value given by the point we were given, which is 3.
So now we have:
y = 0 * x + 3
Which is our solution to the problem! As a shortcut in the future for slope-intercept form equation questions where the slope is 0, it follows y = mx + b, where m is 0, and b is the y value of the given point.
