A rectangle has a perimeter of 88 inches. If the length is 6 more than the width, find the dimensions of the rectangle.

Answer 1

P = 2L + 2w

88 = 2(w+6) + 2w

88 = 2w + 12 + 2w

88 = 4w + 12

76 = 4w

w=19

Rectangle 25 x 19

Answer 2

Let x is Width and (x+6) is length.

Perimeter: P = 2 [x + (x+6) ] = 88 ==> 2 [ 2x + 6 ] = 88 ==> 4x + 12 = 88

==> 4x = 76 ==> x = 19 in

Therefore, width = x = 19 in

length = x + 6 = 25 in

Answer 3

Linda,

The perimeter of a shape is the sum of the lengths of all the sides.

So for a rectangle, the perimeter is (2 * Length) + (2 * Width)

Let’s use L for length and W for width and rewrite this:

Perimeter = 2L + 2W

88 = 2L + 2W

And since length is 6 more than width, we can say L = 6 + W.

Let’s plug this back into the equation so that we have

88 = 2(6 + W) + 2W.

It’s smooth sailing from here!

88 = 12 + 2W + 2W

76 = 4W

W = 19, so your width is 19 inches. Since length is 6 more than width, length is 25. And let’s just double check:

88 = 2(19) + 2(25). ⭐️

Hope this helps! :)