Precalculus solve for x

Question

1 + 2 sin(x) = 0 , xe [ 0 , 360 degrees ]

Answer 1

Grace,

Solve the equation for sin(x) first:

1 + 2 sin(x) = 0 , xe [ 0 , 360 degrees ]

2sin(x) = -1

sinx = -1/2

then look on your unit circle for angles with sinx = -1/2. Sinus is negative in quadrant III and IV, so you will find x = 210 and 330 degrees as solutions. According to the given requirement, your answer must come from the first revolution only, so there are no more possibilities.