Arthur D. answered 01/22/15
Tutor
4.9
(338)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
x=# of liters of the 20% acid solution
(8%)(12)+(20%)(x)=(16%)(12+x)
0.08(12)+(0.2)(x)=(0.16)(12+x)
0.96+0.2x=1.92+0.16x
0.20x-0.16x=1.92-0.96
0.04x=0.96
4x=96
x=96/4
x=24 L of the 20% acid solution