Benjamin L. answered 10/08/19
Supportive and patient mathematics teacher
Expand and combine similar terms: v3(v − 8) − 4v2(5 − 5v) = v4 - 8v3 - 20v2 + 20v3 = v4 + 12v3 - 20v2.
Waleed R.
asked 10/08/19v3(v − 8) − 4v2(5 − 5v) (for the life of me I couldn't find a solution
Benjamin L. answered 10/08/19
Supportive and patient mathematics teacher
Expand and combine similar terms: v3(v − 8) − 4v2(5 − 5v) = v4 - 8v3 - 20v2 + 20v3 = v4 + 12v3 - 20v2.
Nestor R. answered 10/08/19
Professional experienced using mathematics and statistics
v3(v − 8) − 4v2(5 − 5v)
Multiply it out to get
v4 - 8v3 - 20v2 + 20v3
v4 + 12v3 - 20v2
All terms have v2 as a factor
v2 * (v2 + 12v - 20)
Solve the portion within the parentheses using the quadratic formula. Here a=1, b=12, c=-20.
[-b +/- sqrt(b2 - 4ac)] / 2a
Plugging in values for a, b, c into the formula and solving, we get 2 solutions: -13.483315 and 1.483315
Therefore the original string boils down to two possibilities -13.483315v2 and +1.483315v2.
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Waleed R.
I forgot that the 20v^3 should be positive, thanks for the help!10/08/19