Rationalize the denominators of the following fraction: 5/(2- √2)

Question

I need the answer to this ASAP, thanks so much !

Answer 1

1. (5/(2-√2))×((2+√2)/(2+√2) Multiply both top and bottom by the conjugate -> 2+√2
2. 5×(2+√2)÷(2-√2)×(2+√2) -> The bottom one is same as (a+b)×(a-b)= a^2-b²
3. The top one =10+10√2
4. The bottom one =>
5. =(2)²-(√2)²
6. =4-2
7. =2
8. (10+10√2)/2 = 5+5√2