Ethan T. answered 10/03/19
Experienced Math and Physics TA / Tutor
If we have 3 quarts of 20% antifreeze, then we have (0.2)(3 quarts) = 0.6 quarts pure antifreeze in our initial solution. We want to find how many quarts of pure antifreeze we need before we have a 40% solution.
Let's start adding antifreeze. The percentage of solution that is antifreeze can be represented by
% antifreeze = (antifreeze volume)/(total fluid volume)
0.4 = (0.6 quarts + x) / (3 quarts + x), where x is the amount of pure antifreeze we add.
0.4(3 quarts + x quarts) = (0.6 quarts + x)
1.2 + 0.4x = 0.6 + x
0.6 = 0.6x
x = 1 quart
Let me know if that makes sense, the set up can be tricky! If you have other questions send me a direct message and I'll help you out with them.
-Ethan