Let x = number of $5 increases
R(x) = revenue for x $5 increases = (number of tickets sold)(Price per ticket) = (30000 - 500x)(200 + 5x)
The graph of y = R(x) is a parabola opening downward. The x-intercepts are 60 and -40.
The maximum revenue occurs halfway between the x-intercepts.
So, maximum revenue when x = 10.In other words, to maximize revenue, the price should be increased 10 times by $5 each time. So, the optimal price would be 200 + 5(10) = $250.
Maximum Revenue = R(10) = (25000)(250) = $6,250,000