Twice the sum of a number and 8 is less than 6

Answer 1

This problem can be represented with the following inequality:

2(x + 8) < 6

To solve the inequality, first divide both sides by 2:

2/2 (x+8) < 6/2

(x+8) < 3

Than subtract 8 from both sides of the inequality:

x + 8 - 8 < 3 - 8

x < -5

This means that any number less than negative 5 is a possible solution for this problem.

Answer 2

Twice the sum of a number and 8 is less than 6:

2(n+8)<6