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Question

What what are the four terms of the sequence defined recursively as: f(1)=4. F(x)=2f(n-1)+2

Answer 1

f(1) = 4

f(2) = 2*f(1) + 2 = 2*4+2 = 8+2 =10

f(3) = 2*f(2) +2 = 2*10+2 = 20+2 = 22

f(4) = 2*f(3)+2 = 2"22+2 = 44+2 = 46

f(5) = 2*f(4) +2 = 2*46+2 = 92 +2 = 94