four consecutive odd integers such that twice the second, added to the last is 25

Answer 1

Four consecutive odd numbers would be

x

x+2

x+4

x+6

Twice the second is 2(x+2)

Added to the last which is x+6 would be

2(x+2)+x+6=25

Distribute the 2

2x+4+x+6=25

Combine like terms

3x+10=25

Subtract the 10 from both sides

3x=15

Divide both sides by 3

x=5

To find the 4 consecutive odd numbers, plug the x back into the 4 original expressions

x=5

x+2=5+2=7

x+4=5+4=9

x+6=5+6=11