One number x is six more than a second number y
x=6+y
Four times the first is 3 less than 5 times the second.
4x=5y-3
Now we substitute the x=6+y into the second equation
4(6+y)=5y-3
Distribute the 4
24+4y=5y-3
Subtract the 4y from both sides
24=y-3
Add 3 to both sides
y=27
Plug this y value into the first equation to obtain the x value
x=6+y
x=6+27=33
To check
33 is 6 more than 27
4 times x which is 4(33) =132 equals
5 times the second minus 3
5(27) -3= 135-3=132