Separate 846 into 3 parts so that the second part is twice the first part and the third part is triple the second part. Which of the following equations could be used to solve the problem?

Answer 1

You did not include any choices of equations, but the problem can be solved as follows:

Let the 3 parts be called A, B, and C.

Let A+B+C = 846

It is given that B = 2*A and C=3*B, but B = 2*A, so C = 2*3*A = 6*A

The sum can be written in terms of A.

A + 2A + 6A = 846

9A = 846.

Divide both sides by 9 to find that A = 94.

B = 2A = 188

C = 3B = 3*188 = 564

94+188+564=846