algebraic math problem

Question

Find three consecutive even integers such that the sum of twice the smallest number and three times the largest is 42.

Answer 1

Let x = the first number

x+2 = the second number

x+4 = the third number

Then,

2x + 3(x+4) = 42

5x = 30

x = 6 (first number)

x+2 = 8 (second number)

x+4 = 10 (third number)