Find two consecutive even integers such that the smaller added to five times the larger gives a sum of 70.

Answer 1

Step 1: Here it is annotated that you have two consecutive integers one being n and another being n+2

Step 2: You can now write it as n+5(n+2) = 70

Step 3: Distribute, which leads you to n+5n+10= 70

Step 4: 6n+10=70

Step 5: 6n= 60

Your Answer: n=10

Answer 2

Two consecutive even integers

n and n + 2

n + 5(n + 2) = 70

Can you solve for n and answer?