Elementary algebra

Question

If 6 is subtracted from the third of three consecutive odd integers and the result is multiplied by 2, the answer is 33 less than the sum of the first and twice the second of the integers. Find the integers.

Answer 1

2(x+4-6) = (x+2(x+2))- 33

2(x-2) = (x+2x+4)-33

2x -4 = 3x +4 -33

2x-4 = 3x -29

-4+29= 3x-2x

25 = x

x = 25

25, 27 and 29 are the 3 consecutive odd integers

2(29-6) = (25+54)-33

2(23) = 79-33

46 = 46

46 =50