The length of a rectangle is five less than twice it’s width. If the perimeter of the rectangle is 56 inches, find it’s dimensions.
Perimeter is 2L + 2W.
You are given a length (L) of 5 less than 2 times the width so L= 2W - 5. The total answer is 56. So set up the equation and solve.
2(2W - 5) + 2W = 56 Solve for W
4W - 10 + 2W = 56
6W - 10 = 56
6W - 10 + 10 = 56 + 10
6W = 66
W = 11
Now you know the width. Plug it back in to the original problem and find the length. Check your answer.
