f(x) = (x - 2i)(x + 2i)[x - (1+√2)][x - (1 - √2)]
= (x2 + 4)[(x - 1) - √2][(x - 1) + √2]
= (x2 + 4)[(x - 1)2 - 2]
= (x2 + 4)(x2 - 2x - 1) = x4 - 2x3 - x2 + 4x2 - 8x - 4 = x4 - 2x3 + 3x2 - 8x - 4
f(x) = (x - 2i)(x + 2i)[x - (1+√2)][x - (1 - √2)]
= (x2 + 4)[(x - 1) - √2][(x - 1) + √2]
= (x2 + 4)[(x - 1)2 - 2]
= (x2 + 4)(x2 - 2x - 1) = x4 - 2x3 - x2 + 4x2 - 8x - 4 = x4 - 2x3 + 3x2 - 8x - 4
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