One number is 9 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 540, find the numbers

Answer 1

x= a number

y= the first number

z=the third number

x=9y

z=100y

x+y+z=540

9y+y+100y=540

110y=540

y=4.9

z=100(4.9)=490

x=(9)4.9=44.2

Answer 2

You have 3 numbers that sum to 540

First number = x

Second number = 9x

Third number = 100 + x

x + 9x + 100 + x = 540

Just combine like terms and solve for x

Give it a try