
Patrick B. answered 09/11/19
Math and computer tutor/teacher
So then 1,2 and 5 are available
since z must map to an odd #, there are 2 possibilities.
w can map to either 2 or the other odd that is not mapped to z.
Therefore there are 4 possible mappings
z-->1 , w -->2, v-->5
z-->1 w-->5, v--->2
z-->5, w--->2, v-->1
z--->5, w--->1, v--->2