Martaeja H.
asked • 09/09/19Find the 4^\text{th}4 th 4, start superscript, t, h, end superscript term in the sequence.
c(n)=−7+6(n−1)
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1 Expert Answer
Patrick B. answered • 09/09/19
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c(n) = -7 + 6(n-1)
c(1) = -7 + 6(1-1) = -7 + 6(0) = -7+0 = -7
c(2) = -7 + 6(2-1) = -7 + 6(1) = -7 +6 = -1
c(3) = -7 + 6(3-1) = -7 + 6(2) = -7 + 12 = 5
c(4) = -7 + 6(4-1) = -7 + 6(3) = 7 + 18 = 25
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Martaeja H.
c(n)=−7+6(n−109/09/19