find three consecutive integers such that the product of the first and second is 20 less than the product of the last two

Answer 1

Let x = the first number

x + 1 = the second number

x + 2 = the third number

Then,

x(x+1) = (x+1)(x+2) - 20 or 2x = 18 or x = 9

So,

the three numbers are 9,10, & 11