Let S = sum of money at the end of the period
So = the initial money invested
I = interest rate
t = time
Then for this case S = So(1 + I)t or 24,400 = 15250(1 + I)10 rearranging we have
24,400/15250 = (1 + I)10 1.6 = (1 + I)10 now take the logarithm of both sides
log(1.6) =(10)log(1 + I) .0204 = log(1 + I) 1 + I = 1.0481
so,
Interest Rate = .0481 or 4.81%
Part 2: For 9% 24,400 = 15250(1 + .09)t or 1.6 = (1.09)t
or log(1.6) = (t)log(1.09) t = log(1.6)/log(1.09) = 5.45 years
So, they would have made the same amount about 4.5 years earlier.