Determine the values of n that satisfy the equation. y=n^2-7n+12, when y=2

Answer 1

y = n² - 7n + 12

Let y = 2

2 = n² - 7n + 12

Subtract 2 from both sides to get

0 = n² - 7n + 10

Factor (n-2)*(n-5)

n = 2, 5

Answer 2

y=n^2-7n+12

2=n^2-7n+12

0=n^2-7n+12

(Factoring the trinomial)

0=(n-3)(n-4)

Hence

n=3, 4