Let x = original length and y = original width
Then, (x+10)(y+10) = xy + 300
So, xy + 10x + 10y + 100 = xy + 300
10x + 10y = 200
Original perimeter = 2x + 2y = 40 cm
Amraney A.
asked 08/29/19if we increase the length and the width of rectangle by 10 cm each. the area of the rectangle will increase by 300 cm^2? The permitter of original rectangle in Cm is?
Let x = original length and y = original width
Then, (x+10)(y+10) = xy + 300
So, xy + 10x + 10y + 100 = xy + 300
10x + 10y = 200
Original perimeter = 2x + 2y = 40 cm
Ray S. answered 08/29/19
Experienced and effective Math Tutor.
Let x & y be the length & the width of the original rectangle respectively, then:
The area of the original rectangle = xy
The perimeter of the original rectangle = 2x + 2y
Now the new rectangle's area:
(x + 10)(y + 10) = xy + 300
xy + 10x + 10y + 100 = xy + 300
10x + 10 = 200 => divide both sides by 5:
2x + 2y = 40 cm
thus:
Perimeter of the original rectangle = 40 cm
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Amraney A.
Thank you08/29/19