A football field is 25 yards longer than three times the width.Its perimeter is 130 yards.Find it’s dimensions

Answer 1

Since length is described in relation to the width, let's assign a variable of W to the width. Three times the width would then be 3W. 25 yards longer than that would be obtained by adding 25 to that...3W + 25. So, the length is 3W + 25 and the width is W.

To find the perimeter of a rectangle, you multiply 2 times the width and the length and add those. So, the perimeter would be 2(W) + 2(3W + 25), and we know that this adds up to 130. After multiplying, we end up with...

2W + 6W + 50 = 130

8W + 50 = 130 (added like terms together)

8W = 80 (subtracted 50 from both sides)

W = 10 (divided both sides by 8)

So, the width is 10 yards. Now, to find the length, substitute that value for W in 3W + 25, which gives us 3(10) + 25 = 30 + 25 = 55 yards.

Final answer: Width = 10 yards, Length = 55 yards

Answer 2

Let l=25 +3w the perimeter is 2l +2w = 130 = 50 +6w +2w so 80= 8w and w=10 yds. and the length = 55 yds.