The probability that the first one is red is 4/9.
The probability that the second one is blue is 3/8 (Since the total now is 8 not 9)
Then the probability of both is (4/9)(3/8) = 12/72 = 1/6 = .167
Ann M.
asked 08/24/19A bag contains 9
marbles: 2
are green, 4
are red, and 3
are blue. Susan chooses a marble at random, and without putting it back, chooses another one at random. What is the probability that the first marble is red and the second is blue? Write your answer as a fraction in simplest form.
The probability that the first one is red is 4/9.
The probability that the second one is blue is 3/8 (Since the total now is 8 not 9)
Then the probability of both is (4/9)(3/8) = 12/72 = 1/6 = .167
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