The probability that at most 12 adults in 100 pass the test is..
100C1(.1)1(.9)99 + 100C2(.1)2(.9)98 + ............................... + 100C11(.1)11(.9)89 + 100C12(.1)12(.9)88
The result of these calculations is .80182 which is the probability
Pegg B.
asked 08/22/19The probability that at most 12 adults in 100 pass the test is..
100C1(.1)1(.9)99 + 100C2(.1)2(.9)98 + ............................... + 100C11(.1)11(.9)89 + 100C12(.1)12(.9)88
The result of these calculations is .80182 which is the probability
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