
Jes V. answered 08/21/19
Math Teacher/Advocate for Mathematical Success
Write an equation of a line in slope-intercept form that passes through (-6,5), and is parallel to -7x + 5y = 57.
Parallel lines have the the same exact slopes! Thus, let’s rewrite the standard-form of the equation in slope-intercept form (y = my + b) where the slope (m) is more visible.
-7x + 5y = 57 First let’s move -7x to the right side of the
+7x +7x equation. Adding 7x to both sides gives:
5y = 7x + 57 Solve for y by dividing both sides by 5:
y = (7/5)x + (57/5) The slope m is (7/5)
Now using our slope of seven-fifths (7/5), substitute into point-slope form given the point (-6,5)
point-slope form of an equation: y - y1 = m(x - x1)
so, y - 5 = (7/5)(x - (-6)) Simplifying gives:
y - 5 = (7/5)x + (42/5) Finally add 5 to both sides to get
+5 +5 back to slope-intercept form,
y = 7 x + 67 thus solving for y to get:
5
or y = 7 x + 67
5 5
*fraction part: 42 + 5 equals 42 + 25 Equals 67
5 5 5 5