f(x) = 1 / (x-2) and g(x) = 2 / (x+3)
domain of f(g(x)) = {x l x is in domain g and g(x) is in domain f}
= {x l x ≠ -3 and 2 / (x+3) ≠ 2} = {x l x ≠ -3 and 2(x+3) ≠ 2} = {x l x≠-3 and x ≠ -2}
f(x) = 1 / (x-2) and g(x) = 2 / (x+3)
domain of f(g(x)) = {x l x is in domain g and g(x) is in domain f}
= {x l x ≠ -3 and 2 / (x+3) ≠ 2} = {x l x ≠ -3 and 2(x+3) ≠ 2} = {x l x≠-3 and x ≠ -2}
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