
Nestor R. answered 08/21/19
Statistician with a very good grounding in Algebra
a / 2/3 is asking "How many times can 2/3 fit into a?"
Rewite the problem as (a/1) / (2/3).
You need to get rid of the (2/3) in the denominator.
The way to do this is by multiplying both the numerator and denominator by the multiplicative inverse of 2/3, namely 3/2
[(a/1) * (3/2)] / [(2/3) * (3.2)]
Note (2/3) * (3/2) is simply 1
Thus [(a/1)*(3/2)] / [(2/3)*(3/2)] becomes [(a/1)*(3/2)] / 1 = (a/1)*(3/2) = a*3/2